**Question 1**

Draw the net of the

*exposed*areas of this shape. Assume that this shape is resting on a table.This is the net.

There are only three rectangles because the

*base*is*not exposed*. Since it's resting on a table, you can't touch it.**Question 2**

Calculate the surface area of the exposed areas.

S.A. = 3(lw) + 2(s²)

= 3(4)(2) + 2(2²)

= 3(8) + 2(4)

= 24 + 8

=

**32m²**

**Question 3**

If a can of paint covers 0.5m², how many cans would it take to cover 32m²?

1 can = 0.5m²

x cans = 32m²

32 = 0.5x

32/0.5 = 0.5x/0.5

64 = x

It will take 64 cans to cover this shape.

________________________________________________________________

After the quiz we learned how to find the surface area of a shape after you put two shapes together.

We have these two shapes and we have to put them together.

When they're connected they look like this.

The red part is the part that is covered. (On Shape 1, the red part is the same as the back.)

**Shape 1**

**Shape 2**

So to find the surface area of the the connected shape, it's easier to do two separate formulas then subtract the area that's touching.

**Shape 1**

S.A. = 2(s²) + 4(lw)

= 2(2²) + 4(3)(2)

= 2(4) + 4(6)

= 8 + 24

=

**32u²**

**Shape 2**

S.A. = 2(lw) + 2(lw) + 2(lw)

= 2(1)(4) + 2(2)(4) + 2(1)(2)

= 2(4) + 2(8) + 2(2)

= 8 + 16 + 4

=

**28u²**

32 + 28 =

**60u²**

Area covered = 2(s²)

= 2(2²)

= 2(4)

=

**8m²**

60 - 8 =

**52u²**

The surface area of the shape is

**52u²**.Here's another way to find out the surface area.

S.A. = 2(s²) + 4(lw) + 2(lw) + P(h) - 2(s²)

= 2(2²) + 4(2)(3) + 2(1)(2) + 6(4) - 2(2²)

= 2(4) + 24 + 4 + 24 - 2(4)

= 8 + 24 + 4 + 24 - 8

=

**52u²**

**Homework:**

- Go on www.studyladder.ca

- Sign in and go to "Set tasks" in Mathematics.

- Do all the homework that Mr. Backe assigned before if you haven't finished it.

- Be ready for the test next week.

- Come to Mr. Backe if you need any help with anything.

The person that I choose to do the next blog post is

**Chelsea.**