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Colleen's Textbook Question 2.4

#29. The speed of sound in air,s, in meters per second , is related to the temperature, t, in degrees Celsius, by the formula s= √401(273+ t). How much greater is the speed of sound on a day when the temperature is 30°C than on a day when the temperature is -20°C? Express you answer to the nearest meter per second. First we have to find the speed of sound on a day when the temperature is 30°C.To find the answer we have to use the formula s=√401(273+ t)

s= √401(273+ t)

s= √401(273+ 30)

To find the answer we have to use BEDMAS

273+30= 303

s= √401(303)

s= √121503

s=348.5728044Then we have to find the speed of sound on a day when the temperature is -20°CTo find the answer we have to use the formula s= √401(273+ t)

s= √401(273+ t)

s= √401(273+ -20°C)To find the answer we have to use BEDMAS273+(-20)= 253s= √401(253)s= √101453

s= 318.5168755

Now that we have found the speed of sound for both temperatures, next we subtract.

348.5728044- 318.5168755= 30.0559289

Since the question says to round to the nearest meter we have to round

30.0559289= 30

The speed of sound is greater by 30m/s on a day that the temperature is 30°C than on a day that is -20°C.
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